Answers

2014-11-01T17:03:58+05:30
We will apply Pitagora, where the diagonal is the hypotenuse 
diagonal^2 = 15^2+8^2
diag^2 = 225+64
diag ^2=289
diag =  \sqrt{289}  \\ diag=17
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2014-11-01T17:05:42+05:30
Length=15cmand breadth=8cm
Lenght of diagonal= \sqrt{l^2+b^2
therfore= \sqrt{ 15^2+8^2
= \sqrt{289=17
Therfore length of the diagonal =17
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