wat is the base of log

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wat is the base of log

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A(log 128 - log 64 + log 1/8) = 2

a(log 2⁷ - log 2⁶ + log 2⁻³) = 2

a( log 2⁷ - log 2⁶ - log 2³) = 2

a(log 2⁷ /(2⁶ x 2³)) = 2

a (log 2⁻²) = 2

a(-2log 2) = 2

a(-2 x 0.301) = 2

a = - 1/0.301

a = - 100/301__ANSWER__

a(log 2⁷ - log 2⁶ + log 2⁻³) = 2

a( log 2⁷ - log 2⁶ - log 2³) = 2

a(log 2⁷ /(2⁶ x 2³)) = 2

a (log 2⁻²) = 2

a(-2log 2) = 2

a(-2 x 0.301) = 2

a = - 1/0.301

a = - 100/301