# In a bag of 10 balls which contain 3 black,4 white,3red balls without replacement.how can we take out 1 black, 1 white,1 red from 10 balls

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Number of black balls = 3

number of ways in which 1 black balls can be taken = ³C₁ = 3

number of white balls = 4

number of ways in which 1 white balls can be taken = ⁴C₁ = 4

number of red balls = 3

number of ways in which 1 red balls can be taken = ³C₁ = 3

so total number of wasy = ³C₁ × ⁴C₁ × ³C₁ = 3×4×3 =**36**

number of ways in which 1 black balls can be taken = ³C₁ = 3

number of white balls = 4

number of ways in which 1 white balls can be taken = ⁴C₁ = 4

number of red balls = 3

number of ways in which 1 red balls can be taken = ³C₁ = 3

so total number of wasy = ³C₁ × ⁴C₁ × ³C₁ = 3×4×3 =