Answers

2014-11-03T23:33:28+05:30
This is A.P
so, let nos. be (a-d),a and (a+d)
by 1st condition,
(a-d)+a + (a+d)=15
so......a=5
now....bye 2 nd condition,
100(a+d)+10a+(a-d)=100(a-d)+10a+)a+d)
so.....198d=594
so.....d=3
We got a=5 and d=3
since we have asummed numbers as (a-d),a and (a+d),,,,,
we get digits..8,5 and 2
so required number is 852



0
how did you assume that digit a+d is in the 100s place? it could be in the 10s place also or units place also.