Answers

2014-03-17T12:07:59+05:30
Volume of iron = (440 * 260 * 100) cm^3. 
Internal radius of the pipe = 30 cm. 

External radius of the pipe = (30 + 5) cm = 35 cm

Let the length of the pipe be 'h' cm

Volume of iron in the pipe = (External volume) – (Internal volume)

[ (\pi * (35)^2 * h) - (\pi * (30)^2 * h)]cm^3 = \pi h * [(35)^2 - (30)^2]cm^3
[(65 * 5) \pi h]cm^3 = (325 \pi h)cm^3
h = ( \frac{440*260*100}{325} *  \frac{7}{22} )cm
h = ( \frac{11200}{100} )m = 112m

So, the length of the pipe is 112 m

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