# 1) Horizontal is same for angle of projection θ and (90-θ).2) a shell is fired at an angle 30° to the horizontal with a velocity 196 m/s. Find the total time of flight, horizontal range and maximum height attained?

2
by 200papi
can u xplin it
nope
i ma sorry i have to go
we know that
range=(u)square sin 2tita /g
then according to question,
range=(196)(196)( sin 2(30))/10 we know g=10
=38416 (root3)/2 /10
=38416(1.7320)/20
t=2u sin(tita)/g
=2(196)sin(30)/10
=392(1/2) /10
h max=(u) square( sin)
square (tita)/2g
=(196)square (sin)square(30)/2(10)
=38416(1/2)(1/2)/20

2014-11-04T14:08:42+05:30
We know that
range=(u)square sin 2tita /g
then according to question,
range=(196)(196)( sin 2(30))/10  we know g=10
=38416 (root3)/2 /10
=38416(1.7320)/20
t=2u sin(tita)/g
=2(196)sin(30)/10
=392(1/2) /10
h max=(u) square( sin)
square (tita)/2g
=(196)square (sin)square(30)/2(10)
=38416(1/2)(1/2)/20
2014-11-04T14:19:45+05:30

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Angle of projection (α) = 30
velocity (u) = 196 m/s

total time of flight =

horizontal range =

maximum height =
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