Answers

2014-11-04T17:31:30+05:30
n3- n
=n(n2- 1)
=n(n-1)(n+1)
if n is even it is divigible by 2. If n is odd then n+1 is even.

(n-1)n(n+1) are three contineous no. so, each value of n, one of them divigible by 3.

Since, n3-n is divigible by 2 and 3, so it must be divigible by 6

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