# Consider a piller of length 10 cm . if a worm climbs 2cm and falls 1cm every 5 minutes to reach its house on top. then how much time would it take to reach its home??????

2

2014-11-06T21:38:37+05:30

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The worm climbs 2 cm and falls 1 cm in 5 minutes.
So it effectively climbs (2-1)=1cm in 5 minutes.

For the first 8cm, it will take (8×5) = 40minutes

At the end of 40 minutes, it will be at 8 cm.

Then in another 5 minutes it will reach the top. Once it reaches the top, it won't fall again.
So the total time is 40+5=45 minutes
• Brainly User
2014-11-06T22:28:41+05:30
Solution :
length of pillar = 10 cm
Effective distance climbed by worm in 5 mins = 2 cm - 1cm
=1cm
So it takes 5 minutes to climb 1 cm .
Therefore time taken to climb 8cm = 8*5
=40minutes.
Now the worm will climb 2cm  to reach 10cm , it wil take him 5 more minutes .

Therefore , total time taken to climb 10cm = 40 +5
=45 minutes!!

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