# Consider a piller of length 10 cm . if a worm climbs 2cm and falls 1cm every 5 minutes to reach its house on top. then how much time would it take to reach its home??????

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The worm climbs 2 cm and falls 1 cm in 5 minutes.

So it effectively climbs (2-1)=1cm in 5 minutes.

For the first 8cm, it will take (8×5) = 40minutes

At the end of 40 minutes, it will be at 8 cm.

Then in another 5 minutes it will reach the top. Once it reaches the top, it won't fall again.

So the total time is 40+5=**45 minutes**

So it effectively climbs (2-1)=1cm in 5 minutes.

For the first 8cm, it will take (8×5) = 40minutes

At the end of 40 minutes, it will be at 8 cm.

Then in another 5 minutes it will reach the top. Once it reaches the top, it won't fall again.

So the total time is 40+5=

length of pillar = 10 cm

Effective distance climbed by worm in 5 mins = 2 cm - 1cm

=1cm

So it takes 5 minutes to climb 1 cm .

Therefore time taken to climb 8cm = 8*5

=40minutes.

Now the worm will climb 2cm to reach 10cm , it wil take him 5 more minutes .

Therefore , total time taken to climb 10cm = 40 +5

=45 minutes!!

Hope this helps You!!

Thank U!!!

Chers!!