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1 pascal is not equal to 760 mm of Hg.

1 pascal = 1 N/m²

density of mercury = 13594 kg/m³

let mercury is present in a tube with base area = 1m²

then we need to find the height for which the pressure is 1 Pascal.

let the height is = h

weight = ρVg = 13594×(h×1)×9.81 = 133357.14h N

pressure = weight/area = 133357.14h N / 1m²

= 133357.14 N/m² = 1 N/m²

⇒ 1 = 133357.14h

⇒ h = 1/133357.14 m

⇒ h = 7.4986×10^-6 m

⇒ h = 7.4986×10^-3 mm

⇒ h = 0.0074986 mm of Hg

So

1 pascal = 1 N/m²

density of mercury = 13594 kg/m³

let mercury is present in a tube with base area = 1m²

then we need to find the height for which the pressure is 1 Pascal.

let the height is = h

weight = ρVg = 13594×(h×1)×9.81 = 133357.14h N

pressure = weight/area = 133357.14h N / 1m²

= 133357.14 N/m² = 1 N/m²

⇒ 1 = 133357.14h

⇒ h = 1/133357.14 m

⇒ h = 7.4986×10^-6 m

⇒ h = 7.4986×10^-3 mm

⇒ h = 0.0074986 mm of Hg

So

**1 Pascal = 0.0074986 mm of Hg**