# Sheila is now 15 years older than her younger brother sanjay.ten years from now,sheila will be twice as old as sanjay.find the present age of each of them

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Let the Present age of Sanjay (in Years ) = x

Therefore , Present age of Sheila = x+15

After 10 years ,

Shielas age = x+15+10

= x+25

sanjay's age = x+10

According to question ,

x+25 = 2(x+10)

x+25 = 2x + 20

25 = 2x + 20 - x

25 = x+20

25 - 20 =x

5 =x

or x=5

Hence

and

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so sheila is x+15

adding ten to both side

x+25=2x+20

x=5

which mean sanjay is 5 years old and sheila is of 15