1)find the value of p for which the points (-5,1),(1,p) and (4,-2) are collinear.2)prove that the points A(-3,3),B(4,3),C(4,-2) and D(-3,-2)are the vertices of the rectangle.3)find the point on x-axis which is equidistant from points (-1,0) and (5,0)guyzzz!!!!!step wise answers plzzz.....need it urgently <hope u understand>

2
by maani
help plzzz!!!1

2014-11-10T20:03:09+05:30

This Is a Certified Answer

Certified answers contain reliable, trustworthy information vouched for by a hand-picked team of experts. Brainly has millions of high quality answers, all of them carefully moderated by our most trusted community members, but certified answers are the finest of the finest.
1. slope of AB = (p-1)/6 = slope of AC = -3/9 = -1/3
p-1 = -2   => p = -1

2.  AB = 7    BC = 5  CD = 7  DA = 5
Slope AB = 0  = parallel to x axis  slope  BC = infinity = parallel to y axis
so perpendicular.  hence proved

3.  let the point be  (x,0).    then   (x+1)^2 = (5-x )^2
so  2x = 4  ie.  x = 2

2014-11-10T20:07:57+05:30
1.
The distance between the (-5,1) & (1,P) is equal to the distance between (1,P) & (4,-2)
therefore,

Both the square root cancels
36 + 1 + P^2 - 2P = 9 + P^2 +4 +4P
Both the P^2 cancels
37 - 2P = 13 +4P
6P = 37-13
P=24
P=24/6
P=4.