## Answers

The largest 3-digit multiple of 7 is 994 = 142*7So there are 142-14 = 128

3-digit multiples of 7, ie 128 3-digit numbers that are divisible by 7.

142 is the ending digit gives 3 digit number when we multiply by 7, 7*142 = 994

Therefore, the total number of digits that gives 3 digit number when we multiply by 7 is 142-15 = 127 and we have to add 1 to 127 because 15 is excluded when we subtract.

so, the answer is 128.

So there are 142 positive integers less than 1000 that are divisible by 7.

100 divided by 7 is 14 with remainder 2.

So there are 14 positive integers less than 100 that are divisible by 7.

Hence there are 142 - 14 = 128 three digit numbers that are divisible by 7