# A beam will be raised into a truck by using the incline along the 2.5 m. The required force of 400 N. If the high-field skewed 2 m, what is the weight of the beam? (Use way)

1
by Leilaaaa

2014-11-15T17:12:08+05:30

### This Is a Certified Answer

Certified answers contain reliable, trustworthy information vouched for by a hand-picked team of experts. Brainly has millions of high quality answers, all of them carefully moderated by our most trusted community members, but certified answers are the finest of the finest.
We assume that the friction force along the inclined plane is not significant.  Also we assume that the beam is pulled along the incline at a small speed and with a  negligible acceleration.

Incline is 2 meters high and the length of the inclined on the ground is 2.5 meters.  So the skew or slope of the incline is 2/2.5 = 0.8

tan Ф = slope of incline,  where Ф = angle of incline.
W = weight of the beam

W Sin Ф = force required to pull the beam = 400 N
W = 400 / √(1+0.8²) = 400/√1.64 = 312.35 Newtons