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2014-11-13T11:12:07+05:30

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No. of red balls = 3
no. of black balls= 5

1. Probability of getting a "red" ball =  \frac{no.\ of\ red\ balls}{total\ no.\ of\ balls } = \frac{3}{8}

2.Probability of getting a "not red" ball
   = 1 - Probability of getting a "red" ball
   = 1-(3/8) 
   =5/8

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2014-11-14T03:57:25+05:30
Given=
No. of red balls = 3
No. of black balls= 5
Total number of ball = No. of red balls + No. of black balls = 3 + 5 = 8

1. Probability of getting a "red" ball = 

2.Probability of getting a "not red" ball 
   1 - 3/8 , 8 - 3/8           =5/8
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