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Find the height of an Isosceles triangle whose each of the equal side measure 45cm and the base is 72cm.And find its area.

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by Elysium

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by Elysium

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Let the height be h

b= base

a= equal sides

so height (h) = √(a² - b²/4)

h = √(45² - 72²/4 )

h = 27 cm

area of triangle = 1/2 x h x b = 1/2 x 27 x 27 = 972 cm²

*ANSWER*

So the height = 27 cm and area = 972 cm²

b= base

a= equal sides

so height (h) = √(a² - b²/4)

h = √(45² - 72²/4 )

h = 27 cm

area of triangle = 1/2 x h x b = 1/2 x 27 x 27 = 972 cm²

Let hight be = h

base=b

area=a

height=(45square - 72square/4)

height=27cm

area=1/2*27*27=972square

base=b

area=a

height=(45square - 72square/4)

height=27cm

area=1/2*27*27=972square