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One end of the diameter of a circle is (-2,5).

Find the co-ordinates of the other end of it, if the centre of the circle is (2,-1).

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Find the co-ordinates of the other end of it, if the centre of the circle is (2,-1).

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[(-2+x)/2 , (5+y)/2] =(2,-1)

(-2+x)/2 =2 , (5+y)/2 =-1

-2+x=4 , 5+y =-2

x=6 ,y=-7

the other end is (6,-7)

The Brainliest Answer!

center of the circle O = (2,-1)

we know that center is the midpoint of the diameter is O (2,-1)

so, [ x₁ + x₂/2 , y₁ + y₂/2 ] = (2,-1)

[ -2 + x₂/2 , 5 + y₂/2 ] = (2,-1)

we know that co-ordinates are equal

-2 + x₂/2 = 2 5 + y₂/2 = -1

-2 +x₂ = 4 5 +y₂ = -2

x₂ = 4 +2 y₂ = -2-5

x₂ = 6 y₂ = -7

the co-ordinates of the other end B = (6, -7)