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2014-11-20T06:24:44+05:30

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1.  the error in measurement could be 1mm. so percentage error is 
       (0.001 m / 0.50 m )*100 = 0.2%

2. chemical balance may have an accuracy of   0.1 mg   or 0.2 mg  , of that order.
       So  % error =  (0.1 mg /1000 mg) * 100 = 0.01%

3.  Let the minimum unit of measurement = 1 sec.  in the stop watch.
       % error = (1 sec / 240 sec)*100 = 0.4 %

   if the stop watch has a resolution of  0.1 sec, then
            % error  =   (0.1 / 240) * 100 = 0.04%

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