Answers

2014-11-19T20:07:40+05:30
(n+2)(n+1)n!=2550*n!
(n+2)(n+1)=2550
(n+2)(n+1)=50*51
soo
n=49
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  • Brainly User
2014-11-19T20:17:46+05:30
(n+2)! can be written as(n+2)(n+1)n!=2550*n!
(n+2)(n+1)=2550
n^2+2n+n+2
=n^2+3n-2548=0
so it can be either 49 or -51 
as n can't be negative so n
=49

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