possible outcomes of 3 times tossing a coin

1st= HHH
2nd= HHT or HTH or THH
3rd= TTHor THTor HTT

Total number of events=8
No of favourable events=6(refer to 2nd and 3rd cases)
P(E)= 6/8=3/4
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Total number  of  outcomes when a coin is tossed 3 times : 2*2*2 = 8
  the two outcomes H or T for each toss is independent of other tosses.  So they are multiplied.

Two outcomes give winning combination = 3 H or 3 T..

Hence probability of failure =  (8-2)/8 = 3/4
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