This Is a Certified Answer

Certified answers contain reliable, trustworthy information vouched for by a hand-picked team of experts. Brainly has millions of high quality answers, all of them carefully moderated by our most trusted community members, but certified answers are the finest of the finest.
We check the 2nd degree polynomial if we can factorize it.  It is not factorizable and it has only imaginary roots.  so we keep it as it is.

\frac{(8-4v+11v^2-2v^3)}{(1-0.25v)(1-v+0.5v^2)} \\\\=\frac{8(8-4v+11v^2-2v^3)}{(4-v)(2-2v+v^2)} \\\\=+16+\frac{A}{4-v}+\frac{Bx+c}{2-2v+v^2}\\

We write +16 on RHS because the coefficient of (highest degree term) v^3 in numerator is -16 and in denominator - 1 * +1 = -1, and hence  -16 v^3/- v^3.

Since 4-v is first degree polynomial, write A in the numerator.  B x +C in the second fraction because the other factor is a second degree polynomial.


Solve the above for A, B and C.
You get answer

1 5 1