# Find the value of A. Sin 120 degrees B. Tan 150 degrees C. Cos (-135 degrees) D. Sec 300 degrees E. Sin 240 - cos 330 degrees

2
by priyankaPillai500

2014-11-28T10:23:39+05:30

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Sin 120 = 2 sin 60 cos 60 = 2 * root(3)/2 * 1/2

Tan 150 = tan (180-30) = - tan 30 = - 1/root(3)

Cos (-135) = Cos 135 = - Cos (180-135) = - Cos 45 = -1/root(2)

Sec 300 = 1/cos 300 = 1/Cos (360-60) = 1/Cos 60 = 2

Sin 240 - cos 330 =  Sin (180+60)  - Cos (360-30) = - sin 60 - cos 30 = 0

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2014-11-28T16:06:18+05:30
Sin 120 = 2 sin 60 cos 60
= 2 × √3/2 × 1/2
=√3/2

B. Tan 150
= tan (180-30)
= - tan 30
= - 1/√3

C . Cos (-135)
= Cos 135
= - Cos (180-135)
= - Cos 45
= -1/√2

D . Sec 300
= 1/cos 300
= 1/Cos (360-60)
= 1/Cos 60
= 2

E . Sin 240 - cos 330
=  Sin (180+60)  - Cos (360-30)
= - sin 60 - cos 30
= 0