A die is thrown 400 times. Each face 1, 2, 3, 4, 5 and 6 appears 75, 60, 65, 70, 68 and 62
times respectively. Find the probability of getting (a) a prime number (b) a number greater
than 4 (c) an odd number

2
have you made this question ??
as you see total out comes is 6 ^400
nah...i haven't
question is from which book

Answers

2014-11-29T21:47:16+05:30

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So probability(p) = no. of events /total out comes

1)so prime numbers are 2,3,5 so total events = 60+65+68 =193
so p = 193/6⁴⁰⁰

2)numbers greater than 4 is 5,6 so total events = 68 + 62 = 130

so p =130/6⁴⁰⁰

3)so odd numbers are 1,3,5 so total events = 75 + 65 + 68 = 208

p = 208/6⁴⁰⁰
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  • Brainly User
2014-11-29T22:13:44+05:30
So probability(e) = possible events /total out- comes

1)So prime numbers are 2,3,5 so total events = 60+65+68 =193
so e = 193/6⁴⁰⁰

2)numbers greater than 4 is 5,6 so total events = 68 + 62 = 130

so e =130/6⁴⁰⁰

3)so odd numbers are 1,3,5 so total events = 75 + 65 + 68 = 208

e = 208/6⁴⁰⁰
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