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Let the height of a right angle triangle be h

let the base of a right angle triangle be b

let the hypotenuse of a a right angle triangle be hy

so sin Ф = h/hy cosec Ф = hy/h

cos Ф = b/hy sec Ф = hy/b

tan Ф = h/b cot Ф = b/h

so cos²Ф + sin²Ф = 1

1 + tan²Ф = sec²Ф

1 + cot²Ф = cot²Ф

cos(90 - Ф) = sin Ф

tan( 90 - Ф) = cot Ф

cosec (90 - Ф) = sec Ф

let the base of a right angle triangle be b

let the hypotenuse of a a right angle triangle be hy

so sin Ф = h/hy cosec Ф = hy/h

cos Ф = b/hy sec Ф = hy/b

tan Ф = h/b cot Ф = b/h

so cos²Ф + sin²Ф = 1

1 + tan²Ф = sec²Ф

1 + cot²Ф = cot²Ф

cos(90 - Ф) = sin Ф

tan( 90 - Ф) = cot Ф

cosec (90 - Ф) = sec Ф

*sin (90° – A) = cos A*

*cos (90° – A) = sin A*

*tan (90° – A) = cot A*

*cot (90° – A) = tan A*

*sec (90° – A) = cosec A*

*cosec(90° – A) = sec A.*

*sin² A + cos² A = 1*

*sec² A – tan² A = 1 for 0° ≤ A < 90°*

*cosec² A = 1 + cot²*

*A for 0° < A ≤ 90º.*