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  • Brainly User
2014-12-02T15:31:43+05:30
See the answer below in attachment
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2014-12-02T15:38:55+05:30

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So you have the formulas as 

for Range( R ) = \frac{u^2sin2\theta}{g}

Max. Height (H) = \frac{u^2sin^2\theta}{2g}

u = initial velocity 
g = acceleration due to gravity
θ = angle of projection

so according to question R = 4H

so \frac{u^2*sin2\theta}{g} = 4\frac{u^2sin^2\theta}{2g}

\frac{4}{4}=tan\theta

θ = 45° ANSWER
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