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2014-12-17T02:55:27+05:30

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Interior angle = 170 deg.

Triangle joining center of polygon O, and two vertices A and B - has angles equal to  170/2, 170/2 and 180 - 170 = 10 deg.

AOB is an isosceles triangle.

angle AOB  = 10 deg.
hence there are 360/10 = 36 sides in the polygon.

each side = 72 feet / 36 = 2 feet = AB

Altitude of AOB = AB/(2 * tan 5 deg) = cot 5

area of one triangle AOB :  1/2 * cot 5 * 2 = Cot 5  square feet

total area of polygon = 36 * Cot 5 deg    square feet


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