# One leg of an isosceles right angled triangle is increased by 6cm and another is increased by 4cm..the change in area is 24 cm^2..So what was the original length of the legs??

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by NamanRockzz

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by NamanRockzz

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Then area of triangle=x²/2

Now the area=(x+4)(x+6)/2

As per question (x+4)(x+6)/2-x²/2=24

⇒ x²+10x+24-x²=48

⇒ 10x=24

⇒ x=2.4

Original length of leg is 2.4 cm