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As x approaches 0 from  negative side,  f(x) approaches - infinity.  As x approaches 0 from positive side, f(x) approaches positive infinity.

  The slope of tangent of f(x) = f '(x) = 2 - 3/x² 

  Slope approaches minus infinity as x tends to zero.  f(x) is discontinuous at x=0.

So the asymptote is x = 0 as the tangent at x=0 (slope is infinity) is perpendicular to x axis.

  f ' (x) = Slope approaches 2, as x tends to infinity.  So there is an asymptote with slope equal to 2 as x tends to infinity.  we have to find its equation.
   f(x) as x tends to infinity is :  2 x + 2 + 3/infinity  or  2 x + 2
   the second asymptote is  y = 2x + 2

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