Answers

2014-12-06T14:42:45+05:30

the probability of getting two no.s whose sum is more than 10 = 1/12

no. of times event takes place=3

no of total events=36

hence probability getting two no.s whose sum is more than 10 =3/36

                                                                                                     =1/12

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2014-12-06T15:18:08+05:30
When two dice are thrownS={(1,1)............(6,6)}          
n(S)=36
A is the event of getting sum of digits more than 10
A={(5,6),(6,5),(6,6)}            
n(A)=3
P(A)=n(A)/n(S)
=3/36
=1/12
When two dice are thrown simultaneously, the probability of getting the sum of the
digit more than10=1/12
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