Answers

2014-12-07T11:50:33+05:30
let radius of the hall = r
As per question= Volume of cylindrical Hall + Volume of dome
                        = πr²*r+ (4/3) πr³/2
                        = πr³ + 2πr³/3 =5πr³/3
then we have    5πr³/3=48510
                              r³=9264.72
                         ⇒  r=21.0028
       Area of floor= πr²=π*441.118=1385.81
                         Floor area is 1385 m²

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Hall height includes dome r+r. It is correct
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