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There are 6 numbers in geometric progression, sum of first three terms is 60 and last three terms is 128 find the first term and common ratio

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by bhavya133

by bhavya133

we got, ar^-2+ar^-1+a = 60

so , r^2+r+1 = 60r^2/a ----(i)

and

ar+ar^2+ar^3 = 128

ar(r^2+r+1) = 128 ------(2)

substituting (1)

gives common difference r= 2√2/∛15

and calculate the later, as I thnk the question is provided with wrong data

please recheck the question