Answers

2014-04-03T15:04:18+05:30
Let the number be , ar^-2,ar^-1,a,ar,ar^2 and ar^3
we got, ar^-2+ar^-1+a = 60
so , r^2+r+1 = 60r^2/a ----(i)

and
ar+ar^2+ar^3 = 128
ar(r^2+r+1) = 128 ------(2)
substituting (1)
gives common difference r= 2√2/∛15
and calculate the later, as I thnk the question is provided with wrong data
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