Answers

2015-01-05T17:07:32+05:30
Molar mass of Al2O3---102gm Therefore, no of moles ---0.051/102 moles =0.0005 moles Therefore no. Of ions present-=0.0005×6.022×10²³ =5×6.022×10^19 =3.011×10^20 molecules
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