Answers

  • Brainly User
2014-12-10T20:11:24+05:30
I assume them to be a-7, a, a+7. Now, (a-7)+(a)+(a+7)=777 → a=259.
Then three consecutive multiple of 7 are 252, 259, 266.
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2014-12-10T20:43:52+05:30
Let 1st multiple of 7 be (7x)----- then:-2nd=7(x+1)--------and the 3rd=7(x +2)so------ 7x + 7x +7 + 7x + 14= 777--------21x + 21= 777---- 21x=777-21----- 21x = 756------ X=756÷21=36----x = 36 1st multiple =7 × 36 =252------2nd multiple =252+7=259---- 3rd multiple =252+14 =266
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