# A chord 10cm long is drawn in a circle whose radius is √50cm find the area of the segments

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by Sria

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by Sria

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We have, radius, r = 5√2 cm and chord length, l = 10 cm.

Now you can observe, ∆OAM & ∆OBM are isosceles & right angled at M.

Here, angle AOM = angle BOM = 45°, then area of ∆ AOB = 25 cm²

and the area of sector AOB = ¼(circle area) = (12.5)π cm², since angle AOB = 90°.

Then area of segments are 50(π-2)/4 and 50(3π+2)/4.