Answers

2014-03-28T18:34:41+05:30
Solution :
Given R1= 12 , R2= 18 and  h = 14
1) Curved Surface area of the cylinder = 2 π r h
Of R1 =2
π12*14
=1055.57
sq.cm
of
R2=2
π18*14
= 1583.36
sq cm

2) Total surface Area
=curved surface areas of R1+
curved surface area of R2
+2
π(R2²-R1²).
=1055.57+1583.36+(2π(324-44))
= 2638.93+2( 565.48)
= 3769.89 sq.cm










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i have trobule with the editing stuff
Solution :
Given R1= 12 , R2= 18 and h = 14
1) Curved Surface area of the cylinder = 2 π r h
Of R1 =2π12*14
=1055.57sq.cm
of R2=2π18*14
= 1583.36sq cm

2) Total surface Area
=curved surface areas of R1+curved surface area of R2+2π(R2²-R1²).
=1055.57+1583.36+(2π(324-44))
= 2638.93+2( 565.48)
= 3769.89 sq.cm
2014-03-29T13:31:19+05:30
Lts curved surface area=1584and total surface area=3769
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