# Three unbaised coin are tossed once .what is the probability of getting at least two heads.

2
by cutekitty

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by cutekitty

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The sample space that can be constructed as follows

s={ TTT,TTH,THT,THH,HTT,HTH,HHT,HHH }

T- denotes tail

H - denotes head

now ,

n( s ) = 8

Let P denote the event of getting atleast 2 heads

{ THH,HTH,HHT,HHH }

n(P) = 4

Probability of at least 2 heads = n(P) /n(s)

= 4/8

= 1/2