# What is the expression for NUCLEAR DENSITY of a nucleus ? Please help soon.Thank You.

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by SURYAKhan954

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by SURYAKhan954

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Nuclear density is the mass density of nucleus of an atom of an element.

Mass M = m * A,

m = mass of a nucleon , = 1.67 * 10^-27 kg

A = mass number of an atom (nucleus)

= total of numbers of protons and neutrons in the nucleus)

Volume V = 4/3 π R³, where R = radius of nucleus

Nuclear density = ρ = M/V = m A / 4/3πR³

R is written as , R = A^¹/³ * R₀ or, R³ = A * R₀³ ,

Where R₀ = mean atomic radius for single nucleon (proton) nucleus.

Then nuclear density = ρ = 3 m / (4π R₀³)

R₀ = for hydrogen atom, for example, 1.25 * 10^-15 meter = 1.25 fm.

Substituting the values for m and R₀, we get,

approximately, ρ = 2.04 * 10^17 kg/m³

Mass M = m * A,

m = mass of a nucleon , = 1.67 * 10^-27 kg

A = mass number of an atom (nucleus)

= total of numbers of protons and neutrons in the nucleus)

Volume V = 4/3 π R³, where R = radius of nucleus

Nuclear density = ρ = M/V = m A / 4/3πR³

R is written as , R = A^¹/³ * R₀ or, R³ = A * R₀³ ,

Where R₀ = mean atomic radius for single nucleon (proton) nucleus.

Then nuclear density = ρ = 3 m / (4π R₀³)

R₀ = for hydrogen atom, for example, 1.25 * 10^-15 meter = 1.25 fm.

Substituting the values for m and R₀, we get,

approximately, ρ = 2.04 * 10^17 kg/m³