#
(i)factorize with detailed explanation

(i)(x^2-3x)(x^2-3x+7)+10

(ii)(x+1)^6-(x-1)^6

answer all questions please

1
by rajusetu

Log in to add a comment

(i)(x^2-3x)(x^2-3x+7)+10

(ii)(x+1)^6-(x-1)^6

answer all questions please

by rajusetu

Log in to add a comment

Certified answers contain reliable, trustworthy information vouched for by a hand-picked team of experts. Brainly has millions of high quality answers, all of them carefully moderated by our most trusted community members, but certified answers are the finest of the finest.

======================

On examining coefficients, rational roots are possibly factors of +10 or -10, ie.,+1,+2,+5,+10,-1,-2,-5-10.

Checking with x =1, P(1) = 0, Hence (x-1) is a factor of P(x),

Checking with x = 2, P(2)=0, Hence (x-2) is a factor too.

P(x) = (x-1)(x-2)(x^2+ax+5) (x^2-3x+2)(x^2+ax+5)

Coefficient of x^3 will be -3+a = -6 , hence a = -3

Factors are : P(x) = (x-1)(x-2)(x^2-3x+5)

the quadratic expression has imaginary roots, as 3^2-4*5 <0. Hence there are no real factors.