# A body travels from A to B with a velocity V1 and return back from B to A with a velocity V2. The average speed of the body during the whole journey is explain with steps

2
by iitjeepraveen

• Brainly User
2014-12-21T18:46:50+05:30
Now, let the distance between A & B be 'd'.
We're gonna use the formula, (Distance)=(Speed)(Time).
Time taken to go from A to B is t1=d/V1.
Time taken to come from B to A is t2=d/V2.
Now, you know that average velocity is (total distance)/(total time).
Then, V(average)=(2d)/(t1+t2)=. You get V(average)=2(V1)(V2)/(V1+V2)
2014-12-22T05:45:40+05:30

### This Is a Certified Answer

Certified answers contain reliable, trustworthy information vouched for by a hand-picked team of experts. Brainly has millions of high quality answers, all of them carefully moderated by our most trusted community members, but certified answers are the finest of the finest.
Time taken to travel from A to B = AB/V1
Time for traveling from B to A = AB / V2

Total Time taken to travel AB and BA,
= AB [ 1/V1 + 1/V2 ] = AB * (V1+V2)/V1* V2

Average speed  =  total distance / total time = 2 * AB / [ AB *  (V1+V2) / V1 * V2 ]
= 2 V1 * V2 / (V1 + V2 ]

Average speed will be the reciprocal of the average of the reciprocals of speeds.