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Base ‘BC’ of an isosceles ∆ABC is 20 cm and equal sides is 26 cm, then the length of altitude through the vertex ‘A’ is

(A)23 cm (B)24 cm (C)25 cm (D)26 cm

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by nishiChopra

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(A)23 cm (B)24 cm (C)25 cm (D)26 cm

by nishiChopra

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Draw a perpendicular from A on to BC. It will meet BC at the center D of BC. This can be show n from the symmetry.

Apply Pythagoras formula in triangle ADB or ADC,

26² = AD² + (BC/2)² = AD² + 10²

AD = 24 cm

Apply Pythagoras formula in triangle ADB or ADC,

26² = AD² + (BC/2)² = AD² + 10²

AD = 24 cm