Draw perpendicular AD In isosceles triangle ABC ,BD =CD=10 cm In right angled triangle ABD use Pythagoras theorem ,h²=p² +b², therefore AD(p)=√676-100=√576=24
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Draw a perpendicular from A on to BC.  It will meet BC at the center D of BC.  This can be show n  from the symmetry.

Apply Pythagoras formula in  triangle  ADB or ADC,
         26² = AD² + (BC/2)² =  AD² + 10²

           AD = 24 cm

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