In youngs double slit experiment the width of the fringes obtained withy ligh of wavelength 5500 angstrom is 3.9mm. calculate the fringe width if the entire apparatus is immersed in a liquid medium of refractive index 1.3

1
by RICHAPawar

2014-12-23T02:11:18+05:30

Certified answers contain reliable, trustworthy information vouched for by a hand-picked team of experts. Brainly has millions of high quality answers, all of them carefully moderated by our most trusted community members, but certified answers are the finest of the finest.
In Young's double slit experiment :

β = fringe width = λ D / d,
D = perpendicular distance between slits and screen
λ = wavelength of light source,
d = distance between slits

velocity in vacuum / velocity in liquid = 1.3
λ  in vacuum * frequency / λ in liquid * frequency  = 1.3
λ in liquid = 5,500 / 1.3  Angstroms

β is proportional to λ , as D and d are same.

β in vacuum / β liquid medium  = λ in vacuum / λ in liquid

β in liquid =  β in vacuum * λ in liquid / λ in vacuum
= 3.9 mm * (5,500 /1.3) Angstrom / (5,500 Angstrom)
= 3.9 / 1.3 =  3 mm