# 30% of the maximum marks are required to pass a test a students gets 135 marks and is declared failed by 15marks find the maximum marks

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by ultrab30

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by ultrab30

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Maximum marks = M

marks obtained by student = 135 and failed by 15 marks. Hence minimum marks to pass are 135+15 = 150.

30% M = 150

30 M / 100 = 150

M = 500

marks obtained by student = 135 and failed by 15 marks. Hence minimum marks to pass are 135+15 = 150.

30% M = 150

30 M / 100 = 150

M = 500

The Brainliest Answer!

marks of a student = 135

failed by= 15

required marks to pass = 135 + 15 = 150

let the total marks be x

then 30% of x= 150

30/100 * x=150

x= 150 * 10/3 = 500

therefore the maximum marks is 500