# A rectangular field has 80 m length and 48 m breadth.three roads each of 2 m pass through the field such that two roads are parallel to the breadth and the third road parallel to the length.find the area covered by the three roads

2
by raviverma02486

2014-12-26T15:15:24+05:30
We know that width of each road is 2m.
Length of one road (parallel to the length) = length = 80m.

= 2( 2*48)
= 2(96)
= 192 m. square
ii] Area of road parallel to the length = width of road * length
= 2 * 80
=  160 m. square
Now, subtract the areas common in both the roads :
We can see that the length and breadth of these common areas is 2 m.
Areas of the common part = (2*2) + (2*2)
= 4 + 4
= 8 m. square
Upon subtracting these from the total area of the roads :
(192 + 160) - 8
344 m. square
The area covered by the three roads is 344 m. square.

Look at the attachment.
2014-12-27T18:32:20+05:30
Length of two roads are 48 m each  and width=2 m
Area of these two roads= 2*48*2= 192 m²
Length of one road is 80 m
Area of this road = 80*2=160 m²
Common area of these roads= 2*2*2= 8 m²
Area covered by three roads =192 + 160 - 8 = 344 m²
The area covered by three roads= 344m²