Answers

  • Brainly User
2014-04-01T19:04:08+05:30
Let the center of mass be at origin with disc in x-y plane
so when disc of R/2 is removed
the center of mass is
( \frac{- \pi  \frac{R^2}{4} \frac{R}{2}  }{ \pi  \frac{3R^2}{4}},0 )=(- \frac{R}{6},0 )
so the center of mass is at a distance of R/6 from center on side opposite to portion where portion was taken
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