# A body dropped from certain height h reaches the ground after certain time t .after half of the time its height above ground is given 3h/4 bt hw ?explain?

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by kitty4keer

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by kitty4keer

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H=(0.5*a* T^2)/4= h/4. This implies the distance of the object above the ground is h-h/4=3h/4

A=9.8

t=t

u=0

s=ut+1/2at²

=1/2at²=h

t=t/2

H=1/2 X a X t²/4=h/4

height from ground=h-h/4=3h/4

t=t

u=0

s=ut+1/2at²

=1/2at²=h

t=t/2

H=1/2 X a X t²/4=h/4

height from ground=h-h/4=3h/4