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2015-01-01T03:07:35+05:30

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Using the first law of Thermodynamics : dQ = dU + P dV
         dQ = 0 as no heat is given to the system or taken out from the system.

       dU = μ C_v  dT           and   Hence,     
         μ C_v dT = - P dV

As pressure is constant,  μ C_v ΔT = - P ( V2 - V1 )

              C_v = 3/2 R for a monoatomic gas

   R = 8.314 J/mol/K       μ = 1 mole      V2 = 2 * 10⁻³ m³     V1 = 1 * 10⁻³  m³
   P  = 1.013 * 10⁵ N/m²

         ΔT = 8.12 ° K  

       this seems to be same as   2 / (3*0.0821)

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