# When one mole of a monoatomic ideal gas at T kelvin undergoes adiabatic change under a constant external pressure of 1 atm changes volume from 1 to 2 litres. The final temperatue in kelvin is? answer:- T+ { 2 / (3*0.0821)}

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by pslibra21

2015-01-01T03:07:35+05:30

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Perhaps there are more than one way of doing this.

Using the first law of Thermodynamics : dQ = dU + P dV
dQ = 0 as no heat is given to the system or taken out from the system.

dU = μ C_v  dT           and   Hence,
μ C_v dT = - P dV

As pressure is constant,  μ C_v ΔT = - P ( V2 - V1 )

C_v = 3/2 R for a monoatomic gas

R = 8.314 J/mol/K       μ = 1 mole      V2 = 2 * 10⁻³ m³     V1 = 1 * 10⁻³  m³
P  = 1.013 * 10⁵ N/m²

ΔT = 8.12 ° K

this seems to be same as   2 / (3*0.0821)