# A cylinder contains 68g of ammonia gas at stp. 1. What is the volume occupied by this gas ? 2. How many moles of ammonia are present in the cylinder? 3. How many molecules of ammonia are present in the cylinder? N=14, h=1

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• Gun
• Ambitious
2014-12-29T18:18:31+05:30
RMM of ammonia = 14 + 1*3 = 17
No. of moles - 68/17 = 4
Volume = 22.4*4 = 89.6 LITRES
NO. of molecules = 4 * Avogadro's no. = 4 * 6.022 * 10^23
2014-12-31T20:47:37+05:30

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Ammonia gas is  N H₃ .  Molecular mass = 14 + 3 = 17 amu

Number of moles of Ammonia in 68 gms = 68/17 = 4 moles

1 mole of an ideal gas occupies 22.4 liters at STP
Hence 4 moles occupy 4 * 22.4 = 89.6 liters

Number of molecules present in four moles of an ideal gas at any temperature and pressure = 4 * Avogadro number = 4 * 6.023 * 10^23