Answers

2014-12-29T23:15:05+05:30

Latent heat of vaporization of water = 22.5 X 10 to the power 5 J/kg.

or 1 kg of water needs = 22.5 X 10 to the power 5 J/kg.

or 4 kg of water needs = .34 X 10 to the power 5 J/kg X 4

or 9 X 10 to the power 6 J/kg.

1 4 1
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2014-12-29T23:42:54+05:30

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Latent heat of vapourisation of water = 2260 kJ/kg
to convert 4kg of water into vapour, total heat needed = 4×2260 = 9040 kJ
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That much heat is required only for the conversion of water at 100 degree celcius.