Answers

2014-04-02T15:28:25+05:30
(a+b+c)³ = a³+b³+c³+2a²b+3a²c+3b²a+3b²c+3c²a+3c²b+6abc
Therefore,
a³+b³+c³ = (a+b+c)³-3(a²b+a²c+b²a+b²c+c²a+c²b+2abc)
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The Brainliest Answer!
2014-04-02T15:54:26+05:30
A^3+b^3+c^3= (a+b+c)(a^2+b^2+c^2 -ab-ac-bc)+3abc
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