# There is a rhombus with one of its angle 70 degrees and the perimeter of the rhombus is 20 cm. find the sides of the shape and also construct it

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by simratsahota

2015-01-02T10:49:20+05:30
Perimeter of rhombus is 20cm
Hence the length of side =20/4= 5 cm
Let the Rhombus be ABCD.
1. Draw line  using scale and mark AB=5 cm
2. At A draw angle OAB = 70 degree using protractor.
3. Mark point D on AO using compass where AD=5 cm
4. Using D and B as centers draw arcs with radius 5 cm .
5. Let the arcs intersects at C.
6. Join DC and BC  to get Rhombus ABCD.
2015-01-02T10:51:07+05:30

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The cyclical  quadrilateral Rhombus has all its sides equal.  The angles (opposite) are equal.  Adjacent angles are supplementary (sum to 180 deg).

Side = perimeter / 4 = 5 cm

The two different Angles are : 70 deg and 180 - 70 = 110 deg.

1. Draw a line segment AB horizontally of length 5 cm.
2. Draw a line segment (from A) at an angle of 70 deg to AB using a protractor.  Measure 5 cm from A on this line and mark it as C.  Or, using a compass draw an arc with radius 5 cm with center as A to cut this inclined line at point C.

3. Draw a line segment from B at angle of 110 deg to AB, on the same side as AC.

4. Now using a compass draw an arc with radius 5 cm to cut the inclined line at D.

Join ABCD, to get the Rhombus.

Can u explain clearly