# There is a rhombus with one of its angle 70 degrees and the perimeter of the rhombus is 20 cm. find the sides of the shape and also construct it

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by simratsahota

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by simratsahota

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The cyclical quadrilateral Rhombus has all its sides equal. The angles (opposite) are equal. Adjacent angles are supplementary (sum to 180 deg).

Side = perimeter / 4 = 5 cm

The two different Angles are : 70 deg and 180 - 70 = 110 deg.

1. Draw a line segment AB horizontally of length 5 cm.

2. Draw a line segment (from A) at an angle of 70 deg to AB using a protractor. Measure 5 cm from A on this line and mark it as C. Or, using a compass draw an arc with radius 5 cm with center as A to cut this inclined line at point C.

3. Draw a line segment from B at angle of 110 deg to AB, on the same side as AC.

4. Now using a compass draw an arc with radius 5 cm to cut the inclined line at D.

Join ABCD, to get the Rhombus.

Side = perimeter / 4 = 5 cm

The two different Angles are : 70 deg and 180 - 70 = 110 deg.

1. Draw a line segment AB horizontally of length 5 cm.

2. Draw a line segment (from A) at an angle of 70 deg to AB using a protractor. Measure 5 cm from A on this line and mark it as C. Or, using a compass draw an arc with radius 5 cm with center as A to cut this inclined line at point C.

3. Draw a line segment from B at angle of 110 deg to AB, on the same side as AC.

4. Now using a compass draw an arc with radius 5 cm to cut the inclined line at D.

Join ABCD, to get the Rhombus.