# Using 5 numbers in 1,3,5,7,9,11,13,15 make 30.there will not be more or less than 5.every number can repeat as u like for 5 times. GOOD LUCK.................................................................................................................................

2
by rithikhenry136

2015-01-03T13:34:11+05:30

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Gaurav Agrawal (IAS) answered very intelligently in 2014 using his imagination as 3! + 3! + 3! + 3! + 3! = 30

This question is asked so many times.. all credit goes to him.  The following ways are my suggestions.

I can answer this question in many ways using the factorial function.

3! + 1 + 3 + 9 + 11          = 30
1 + 5 + 7 + 3! + 11               = 30
3! + 3! + 3! + 11 + 1             = 30
3! + 3! + 11 + 5 + 1               = 30
11+ 1 + 1 + 3! + 11              = 30
15 + 3 + 3 + 3 + 3!              = 30
13 + 1 + 1 + 9 + 3!            = 30
13 + 1 + 3 + 7 + 3!            = 30
13 + 5 + 3 + 3 + 3!            = 30

If  one can use /, * , exponent and other operators, then you can get more answers too.  Question does not say anything about the operators.

5 * 3 + 13 + 1 + 1 = 30
13 + 15 + 3! - 3 - 1 =    30
15! / 13! / 7 * 1 * 1  =  30
5!  / 3!  + 1 * 3 + 7 = 30
7 * 5  - 3 - 1 - 1  =  30
9 * 7 / 3 + 9 * 1 =  30
3³ + 1 + 11 - 13 * 1  = 30
5³ / 15 * 3 + 5 * 1 = 30
3 * 15 - 11 - 3 - 1 = 30

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You need one operator for which the result is an even number with an input being an odd number.  Factorial is one.  Probably there are other operators too.